Matematika Q.uitt-------------------------------------------f(x) = 42x² × x!! + 2xf(4) = ....--------------------------------------------RULES .-.• Pakai cara ygy.• ngasal? report -_-• Rapi ygy.• Lengkap = beA :v• Good luck .-.-----------------------------------------_.​

adrienkshlerinulv – March 09, 2023

Q.uitt
-------------------------------------------
f(x) = 42x² × x!! + 2x
f(4) = ....
--------------------------------------------
RULES .-.
• Pakai cara ygy.
• ngasal? report -_-
• Rapi ygy.
• Lengkap = beA :v
• Good luck .-.
-----------------------------------------
_.​

.-. Penyelesaian :

f(x) = 42x² × x!! + 2x

f(4) = ... ?

------------------------------------------------

f(4) = 42(16) × 4!! + 2(4)

f(4) = (42 × 16) × (4 × 2) + (2 × 4)

f(4) = 672 × 8 + 8

f(4) = 5.376 + 8

f(4) = 5.384

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[tex]\colorbox{black}{\pink{\boxed{✿✧ \: \colorbox{black}{ \purple{\boxed{\tt{ \: \blue{❛❜ \: Rixxel} \: \red{x} \: \pink{Reina \: ❛❜} \: }}}} \: ✧✿}}}[/tex]

[tex]f(3) = 42(4²) × 4!! + 2(4)\\f(3)= 42(4 \times 4) × 4!! + 2(4)\\f(3)= (42 \times16) × 4!! + 2(4)\\f(3)= (672 × 8) + 2(4)\\f(3)= 5.376 + (2 \times 4)\\f(3)= (5.376 + 8)\\f(3)= \sf\pink{{{5.384}}}[/tex]

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